|Fundamentals of Statistics contains material of various lectures and courses of H. Lohninger on statistics, data analysis and chemometrics......click here for more.|
|See also: level of significance, hypothesis testing|
Interpreting p values
For statistical tests there is one value which specifies the strength
of its evidence:
An example should clarify the point:
Suppose you have to decide whether there are any differences in the wear and tear of truck tires between two different brands. The null hypothesis will be that the wear does not differ, the alternative hypothesis is that they do differ. Assuming that the data (18 samples each) is normally distributed and the means (2.03 and 2.69 mm) and standard deviations (1.30, and 1.11, respectively) are known, we can calculate the test statistic t=1.762.
Using the t-distribution, we can find the corresponding p-value of 0.086. This means that in 86 out of 1000 cases, the test statistic will exceed the value of 1.762, although the null hypothesis is true. Or, in other words, if you reject the null hypothesis, you commit a mistake in 8.6 percent of the cases.
Last Update: 2012-10-08